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Monday, December 10, 2012

LeetCode: Remove Duplicates from Sorted List II

Remove Duplicates from Sorted List II
Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.
For example,
Given 1->2->3->3->4->4->5, return 1->2->5.
Given 1->1->1->2->3, return 2->3.

public class Solution {
    public ListNode deleteDuplicates(ListNode head) {
        // Start typing your Java solution below
        // DO NOT write main() function
        ListNode prev = new ListNode(0);
        prev.next = head;
        head = prev;
        
        ListNode n1=head;
        while(n1.next!=null){
            ListNode n2=n1.next;
            while(n2.next!=null && n2.next.val==n2.val){
                n2=n2.next;
            }
            if(n2!=n1.next){
                n1.next=n2.next;
            }else{
                n1=n1.next;   
            }
        }
        return head.next;
    }
}

3 comments:

Anonymous said...

Thank you!

Unknown said...

what if the list is 1->1 ? the expect result should be null, but will this algorithm return 1?

Temporo said...

With a safe guard node at the front of the list, it will not return 1.